# How can I check my answer?

#### Gavriell

##### New member
How can I check my answer? can I just plug t into the final parametric equation and check if I get the same given points?

#### Jomo

##### Elite Member
The 1st equation in which you solved for t also has the result of t=-2. Will this change anything?

#### Gavriell

##### New member
The 1st equation in which you solved for t also has the result of t=-2. Will this change anything?
Yes, -2 does not satisfy the other two equations.

#### pka

##### Elite Member
The 1st equation in which you solved for t also has the result of t=-2. Will this change anything?
$$\displaystyle -2$$ is not in the domain of $$\displaystyle \vec{r}$$, because $$\displaystyle \log(t+1)-\exp(t)$$ would not exist for $$\displaystyle t=-2$$.

#### Gavriell

##### New member
$$\displaystyle -2$$ is not in the domain of $$\displaystyle \vec{r}$$, because $$\displaystyle \log(t+1)-\exp(t)$$ would not exist for $$\displaystyle t=-2$$.
does that mean that the answer is correct?

#### pka

##### Elite Member
does that mean that the answer is correct?
It should be $$\displaystyle \vec{v}(0)+t~\vec{v}~'(0)$$