How can I check my answer?

Gavriell

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Mar 8, 2019
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How can I check my answer? can I just plug t into the final parametric equation and check if I get the same given points?


12840
 

Jomo

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The 1st equation in which you solved for t also has the result of t=-2. Will this change anything?
 

Gavriell

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Mar 8, 2019
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The 1st equation in which you solved for t also has the result of t=-2. Will this change anything?
Yes, -2 does not satisfy the other two equations.
 

pka

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Jan 29, 2005
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The 1st equation in which you solved for t also has the result of t=-2. Will this change anything?
\(\displaystyle -2\) is not in the domain of \(\displaystyle \vec{r}\), because \(\displaystyle \log(t+1)-\exp(t)\) would not exist for \(\displaystyle t=-2\).
 

Gavriell

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Mar 8, 2019
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\(\displaystyle -2\) is not in the domain of \(\displaystyle \vec{r}\), because \(\displaystyle \log(t+1)-\exp(t)\) would not exist for \(\displaystyle t=-2\).
does that mean that the answer is correct?
 

pka

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does that mean that the answer is correct?
Yes! As far as I can follow your workings.
It should be \(\displaystyle \vec{v}(0)+t~\vec{v}~'(0)\)
 
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