How did they get the complex roots?

[thisonedude]

So in the answer, they found the complex roots as being 1-2j and 1+2j however, when i did the quadratic formula as being -1+8j and -1-8j, Why is theirs right and mine not?

 

[Ishuda]

So in the answer, they found the complex roots as being 1-2j and 1+2j however, when i did the quadratic formula as being -1+8j and -1-8j, Why is theirs right and mine not?

What are you trying to find the complex roots of? The two roots 1$\displaystyle \pm$2j are roots to
$\displaystyle (s-1)^2 + 4 = 0$.
The two roots -1$\displaystyle \pm$8j are roots to
$\displaystyle (s+1)^2 + 64 = 0$.

Neither of those polynomial expressions appear in your formulas. Of course, if the two roots were -1$\displaystyle \pm$2j it would be a different story.

 

[Deleted member 4993]

So in the answer, they found the complex roots as being 1-2j and 1+2j however, when i did the quadratic formula as being -1+8j and -1-8j, Why is theirs right and mine not?

Short answer - you must have made a mistake. Since we cannot see your work - we cannot tell what/where you made the mistake.

Please show all the steps of your solution - and we might be able to catch your misstep.

 

[thisonedude]

What are you trying to find the complex roots of? The two roots 1$\displaystyle \pm$2j are roots to
$\displaystyle (s-1)^2 + 4 = 0$.
The two roots -1$\displaystyle \pm$8j are roots to
$\displaystyle (s+1)^2 + 64 = 0$.

Neither of those polynomial expressions appear in your formulas. Of course, if the two roots were -1$\displaystyle \pm$2j it would be a different story.

I'm trying to find the roots of s² ​+2s + 5

 

[stapel]

I'm trying to find the roots of s² ​+2s + 5

What did you get when you plugged "s^2 + 2s + 5 = 0" into the Quadratic Formula?

 

[Ishuda]

I'm trying to find the roots of s² ​+2s + 5

You can use the quadratic formula or note that, as written in the original post that
$\displaystyle s^2 + 2 s + 5 = (s+1)^2 + 4$
and if you want the roots of the equation you have
$\displaystyle s^2 + 2 s + 5 = (s+1)^2 + 4 = 0$
=> $\displaystyle (s+1)^2 = -4$
=> $\displaystyle (s+1) = \pm 2j$
or
$\displaystyle s = -1 \pm 2j$

The quadratic formula gives the same result:
$\displaystyle s=\frac{-2\pm\sqrt{2^2-4*1*5}}{2}=\frac{-2\pm\sqrt{-16}}{2}=\frac{-2\pm4j}{2}= -1 \pm 2j$
so it appears that you made a mistake somewhere (did you forget to take the square root of 16?).