bookishkelly
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- Jan 29, 2019
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OK. This problem is designed to show a very simple practical application of trig functions (indeed this trype of problem is why trig functions were originally invented over 2000 years ago).Hi could someone please explain how to answer these two questions? Right now we just started learning cosine, sine, and tangent in geometry, if that helps.
Are you allowed to use calculator?What is the measure of each angle in the triangle ABC?= m<A is 25, m<b is 90, m,C is 65
The cosine of angle ACB = the ratio of what 2 sides of the triangle? cosine of angle ACB is 25/hypotenuse
The sine of angle BAC = the ratio of what 2 of the triangle? - sine of angle BAC is opposite leg/hypotenuse
How do those help answer this problem? - Unfortunately, I still don't know how to solve the problem. The sides don't have any values so I can't plug any number in.
Well it did not help that I did not indicate the functions most useful for this problem. Not the most helpful clue. Sorry about that.What is the measure of each angle in the triangle ABC?= m<A is 25, m<b is 90, m,C is 65
The cosine of angle ACB = the ratio of what 2 sides of the triangle? cosine of angle ACB is 25/hypotenuse
The sine of angle BAC = the ratio of what 2 of the triangle? - sine of angle BAC is opposite leg/hypotenuse
How do those help answer this problem? - Unfortunately, I still don't know how to solve the problem. The sides don't have any values so I can't plug any number in.
OK. This problem is designed to show a very simple practical application of trig functions (indeed this trype of problem is why trig functions were originally invented over 2000 years ago).
What is the measure of each angle in the triangle ABC?
The cosine of angle ACB = the ratio of what 2 sides of the triangle?
The sine of angle BAC = the ratio of what 2 of the triangle?
How do those help answer this problem?
Maybe in a few more years.a) the question is what is the length of side ac
sin65=ab/ac; you know ab=25 feet, solve for ac
b) the question is what is the length of side ad
sin62=ad/ab; you know ab=25 feet, solve for ad
redraw the picture for yourself with sides labeled,
and apply sin=opposite/hypotenuse.
[rule 1- always draw a picture, do not spare the pencils and paper.]
it will come to you.
Maybe in a few more years.