My mistake, I meant 3 bits is one zero in a ordinary number. 10 bits, is 3 bytes. 1GB of 1s & 0s in binary can store sooooo many entities. Image 10 bits. 10 bits is really 1,000. Now imagine 1,000 entities - 000000000000000000000000000000000000000000000000................. Now images what not 10 bits is, but 800,000,000,000 bits is!
The 9^9=n was about using very little bits to make a big number. I want to make 10MB into 100 bytes, 9^9 ^ 9 ^ 9 ^ 9 ^ 9 can generate a number so big we can't even run the calculation. Unfornunately I don't know how to control it enough. So many big results, so few starter bits, not possible really.....but for some cases, yes! I can generate a huge movie using a few bits. Imagine that!
I think you may be confusing
binary and
decimal - and something more. A byte is not a decimal digit, but 8 binary digits.
The fact that we can store 1000 in 10 bits means that, for example, the decimal ("ordinary") number 1000, written in binary, is 1 111 101 000, which takes 10 bits (binary digits). With ten bits, you can store any of 1024 different numbers (one at a time, of course).
What you apparently mean by "3 bits is one zero" is that each digit in a decimal number (that is, each factor of 10) corresponds to about 3 bits. As we've said, 3 bits actually holds 8 numbers (0 through 7: 000, 001, 010, 011, 100, 101, 110, 111), so you're slightly overestimating it.
But the rest of what you're saying makes no sense at all, in terms of what bits actually mean.
Your second paragraph suggests that
you aren't thinking of number systems and bytes and bits at all, but about a very different challenge: how large a number can you express using a given small number of
characters in a mathematical expression; or, conversely, how few symbols can you use to express a given large number (which is a much harder challenge). Yes, some special numbers can be obtained very compactly, but that doesn't mean that any given number can - for exactly the reason we've been discussing.
Sometimes we see discussions about what is the largest number you can "write with three digits". They will say 9^(9^9); but depending on the rules of the game, 9!^(9!^9!) is much bigger, and you can go far higher than that. But that's just a silly puzzle, not something interesting about actually representing numbers in general. Most numbers can't be written so compactly.
Am I guessing correctly what you have in mind?