x dy/dx +y-e^x= 0 What method would you go about by solving this? WOuld you use dy/dx + Py = Q?
Yes - and the integrating factor would be \(\displaystyle e^{\int P(x)dx}\) where P(x) =\(\displaystyle \dfrac{1}{x}\) and Q(x) = \(\displaystyle \dfrac{e^x}{x}\)
If the question is the integral of px then what part does qx play?
If the question is the integral of px then what part does qx play?
so do you solve it like this:
d/dx (y*e^ integral 1/x dx)=((e^x)/x)* e^(integral 1/x dx)
Is that right?
so do you solve it like this:
d/dx (y*e^ integral 1/x dx)=((e^x)/x)* e^(integral 1/x dx)
Is that right?
Do you not know what \(\displaystyle \int 1/x dx\) is? If you do, why have you not put it in? This is a very very simple integration problem.so do you solve it like this:
d/dx (y*e^ integral 1/x dx)=((e^x)/x)* e^(integral 1/x dx)
Is that right?