D dedwards New member Joined Sep 3, 2008 Messages 9 Sep 5, 2008 #1 how many 5 digit codes are possible if 0 cannot be used and no digit can be repeated? 10 in the first possible set so 10 x 5 = 50 50 x 50=100..im stuck
how many 5 digit codes are possible if 0 cannot be used and no digit can be repeated? 10 in the first possible set so 10 x 5 = 50 50 x 50=100..im stuck
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Sep 5, 2008 #2 Re: help Without 0 there are 9 choices for the first. 8 for the second. 7 for the third and so on. Can you get it now?. Or just think of it as choosing 5 items out of 10 where order matters. P(9,5)
Re: help Without 0 there are 9 choices for the first. 8 for the second. 7 for the third and so on. Can you get it now?. Or just think of it as choosing 5 items out of 10 where order matters. P(9,5)
