Yes, but I may have omitted some important info through ignorance more than intention. If it is ok I am going to change the formula slightly so that with all of your help I will be able to answer the original in the future on my own.

Here is the new equation including the full question...

A sinusoidal voltage source (v(t)=12V*sin(wt) is connected across a 5k ohm resistor.

1) make a sketch of the p(t), the instantaneous power supplied by the source

Thanks for providing the actual question. I'm not sure how "ignorance" would lead to entirely dropping "sin", but we can more on.

The "sin" is what it means to be a "sinusoidal voltage source". I wouldn't have put V for volts in the middle of an expression, but I guess we have to assume it means v(t) = 12sin(wt), where t is time (in seconds?) and w (actually the Greek letter omega, ω) is the frequency.

The next question we need to ask is, what do you know about this subject? I see you are familiar with facts like P = VI and V = IR, which Khan referred to a couple times. But what do you know about sinusoidal functions? We really need to know what we can expect you to understand, in order to help.

so far I have calculated that

1. Current (I)= 2.4A (V/R=I)

2. Power (P) = 28.8W (I*V=P)

3. Volt (V) = 12v (provided)

4. Resistance (R) = 5 ohm (provided)

The trouble here is that, unless I'm reading something wrong, you are

**not **told that the voltage is a

**constant **12 V; that's the point of calling it

**sinusoidal**. So you appear to be ignoring the main point of the problem. On the other hand, there's not much more to do.

What is the context of the question?