James10492
Junior Member
- Joined
- May 17, 2020
- Messages
- 50
Hi I've got a cubic expression I need to factorise and I am really stuck. Currently I am doing graph transformations and the problem arose with a question where you are given a function f(x) = (x-1)(2x-3)(4-x) and you then have to give the function for the transformed graph f(x) + 2 in its fully factorized form.
The way I have approached this is to multiply out the brackets for the original function f(x), add 2, and then try to factorize the result (like breaking it apart and putting everything back together again). After multiplying out and adding 2 I get -2x3 +13x2 -23x + 14, an expression where x isn't a factor. I have tried the trial and error method of finding a factor (by substituting numbers into f(x)) but to no avail. I can't help but feel that maybe I am trying too hard. Am I missing some kind of short cut method to factorise the new function with the transformation? This is a new topic for me so I wanted to make sure. Thanks for reading, any help would be greatly appreciated.
The way I have approached this is to multiply out the brackets for the original function f(x), add 2, and then try to factorize the result (like breaking it apart and putting everything back together again). After multiplying out and adding 2 I get -2x3 +13x2 -23x + 14, an expression where x isn't a factor. I have tried the trial and error method of finding a factor (by substituting numbers into f(x)) but to no avail. I can't help but feel that maybe I am trying too hard. Am I missing some kind of short cut method to factorise the new function with the transformation? This is a new topic for me so I wanted to make sure. Thanks for reading, any help would be greatly appreciated.