how to get 2.8 + j3.5 m^(-1) from square root in first line?

sasuki

New member
Joined
Oct 9, 2015
Messages
3
can any one help with this equation ASAP PLZ

\(\displaystyle =\, \sqrt{\strut \left[20\, +\, j\,(6\, \times\, 10^8)\,(0.4\, \times \,10^{-6})\right]\, \left[80\, \times \,10^{-3}\, +\, j\,(6\, \times \,10^8)\,(40\, \times \,10^{-12})\right]\,}\)

\(\displaystyle =\, 2.8\, +\, j\,3.5\, m^{-1}\, =\, \alpha\, +\, j\beta\)

how we get the second line from the first line and what M to the power of -1 symbol means

thanks in advance :D
 
Last edited by a moderator:
can any one help with this equation ASAP PLZ

\(\displaystyle =\, \sqrt{\strut \left[20\, +\, j\,(6\, \times\, 10^8)\,(0.4\, \times \,10^{-6})\right]\, \left[80\, \times \,10^{-3}\, +\, j\,(6\, \times \,10^8)\,(40\, \times \,10^{-12})\right]\,}\)

\(\displaystyle =\, 2.8\, +\, j\,3.5\, m^{-1}\, =\, \alpha\, +\, j\beta\)

how we get the second line from the first line and what M to the power of -1 symbol means

thanks in advance :grin:

What is the context of this equation - i.e. - what subject matter gave rise to this equation?

What are your thoughts?

Please share your work with us ...even if you know it is wrong

If you are stuck at the beginning tell us and we'll start with the definitions.

You need to read the rules of this forum. Please read the post titled "
Read before Posting" at the following URL:

http://www.freemathhelp.com/forum/th...Before-Posting
 
Last edited by a moderator:
hello Subhotosh Khan & Denis and any mathematician whom interested thanks for your effort
now it seems that I didn't explain a lot about the topic and what it is about so the topic is about electromagnetic wave and this is the complete slide
attachment.php

here Ive tried to explain in detail the step to solve the equation off course until the part which I don't understand :)
and i hope one of you super mathematician will figure out how to solve it :D
attachment.php



attachment.php


attachment.php



attachment.php

:roll::roll::roll::roll::roll:
 

Attachments

  • bbb.JPG
    bbb.JPG
    77.1 KB · Views: 9
  • 20151010_115456.jpg
    20151010_115456.jpg
    107.1 KB · Views: 10
  • 20151010_115627.jpg
    20151010_115627.jpg
    93.7 KB · Views: 10
  • 20151010_115658.jpg
    20151010_115658.jpg
    93.8 KB · Views: 9
  • 20151010_115739.jpg
    20151010_115739.jpg
    81.9 KB · Views: 9
can any one help with this equation ASAP PLZ

\(\displaystyle =\, \sqrt{\strut \left[20\, +\, j\,(6\, \times\, 10^8)\,(0.4\, \times \,10^{-6})\right]\, \left[80\, \times \,10^{-3}\, +\, j\,(6\, \times \,10^8)\,(40\, \times \,10^{-12})\right]\,}\)

\(\displaystyle =\, 2.8\, +\, j\,3.5\, m^{-1}\, =\, \alpha\, +\, j\beta\)

how we get the second line from the first line and what M to the power of -1 symbol means

thanks in advance :D

Let

A = 6*10^8

B = 4 * 10^(-9)

then we have under radical sign:

[20 + j * A * B * 10^2] * [80 * 10^(-3) + j * A * B * 10^(-2)]

= 1.6 + 20ABE-2 j + 8AB j - (AB)^2

= -4.16 + 8.2*2.4 j

=-4.16 + 19.68

Now convert this to \(\displaystyle e^{i\theta}\) format and use DeMoivre's theorem to calculate the square root.

[ Denis, I am in the corner...]
 
Last edited by a moderator:
guys guys i love the since of the computation that you have & I admire your effort while you competing and showing muscle to each other :grin: there is someone who is not a mathematician and his knowledge about math is just as each course he take require waiting for a magic formula produce from a great mathematician like you just the formula :confused:
 
Top