You should know that \(\displaystyle x^4-11x^3+28x^2=x^2(x^2-11x+28)=x^2(x-7)(x-4)=0\)How would I go about getting the X-intercept to get the critical values to plot.
F(x)=1/2(x^4-11x^3+28x^2)
That has no effect on x-intercepts; all it does is stretch the graph of the function vertically.Thanks that is what I thought it was but I was not sure what you do with that 1/2 outside?
Yes; so the corresponding intercept has multiplicity 2. Do you know what that tells you about the graph?X^2 would be a factor