So you are given 'a' and you need to calculate 'x' - is that the question?dv/dt = a, Here how to integrate dv and how to integrate a.dt? [x^(n+1) /n+1]
Note that a is a constant. We know that all integrals have a constant and we will use v0 for that constant. Why???dv/dt = a, Here how to integrate dv and how to integrate a.dt? [x^(n+1) /n+1]
Note that a is a constant. We know that all integrals have a constant and we will use v0 for that constant. Why???
Int (a*dt) = at2/2 + v0
No, I did not mean that and will edit it. I assumed (bad mistake, I know) that a is constant.You didn't mean that, did you?
The real question here is, IS a a constant? If it is, then ∫dv = v + C1, and ∫a dt = at + C2.
Yes 'a' is a constant (a = acceleration here)You didn't mean that, did you?
The real question here is, IS a a constant? If it is, then ∫dv = v + C1, and ∫a dt = at + C2.
Indranil, have you taken a formal course in calculus?Yes 'a' is a constant (a = acceleration here)
But my question is how do you find 'v', integrating 'dv' and how you find 't', integrating 'dt'? Could you show me the steps, please?
Not yet But here I am learning a great deal from basic to advance from the great teachers like you that's why I don't need to join any formal course and all of you teach here in an amazing way.Indranil, have you taken a formal course in calculus?
Not yet But here I am learning a great deal from basic to advance from the great teachers like you that's why I don't need to join any formal course and all of you teach here in an amazing way.