How to mathematically prove -1 * 1 = 0

ddx

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Dec 8, 2008
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Hey all!

I was hoping someone could help me with this proof. Given 1*1 = 1 and -1*-1 = 1 Prove -1*1 =-1.

I thought it would be as simple as stating the multiplicative identity, but my teacher said no.

How might I accomplish it? It's so easy it's hard.

Thanks!
 
This might be interesting, or it might be trivial. I'm not sure about this one, but have a look at the proof that 1 + 1 = 2, and that might give you some ideas. I'll warn you, though, we're getting into some abstract algebra here, so keep an open mind.

http://mathforum.org/library/drmath/view/51551.html

Just as the proof of 1 + 1 = 2 required a definition for addition, I suspect this one may require a definition of multiplication of integers.
 
I was hoping someone could help me with this proof. Given 1*1 = 1 and -1*-1 = 1 Prove -1*1 =-1.

1. 1 x 1 = 1 given
2. -1 x -1 = 1 given
3. 1 is the identity under multiplication. From (1) only one number with that property
4. -1 x 1 = 1 x - 1 commutative property
5. 1 x - 1 = 1 definition identity element.
That's my answer but to tell the truth I am not sure what can be assumed here and what can't. Some more background from the text might help.
 
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