- Thread starter mchesnutt
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tan(x) = sin(x) * sec(x)

What do you get if you "square" above?

tan

What do you get if divide the above by sec

\(\displaystyle \dfrac{\tan^2(x)}{\sec^2(x)}\) = ?

Now evaluate:

1- \(\displaystyle \dfrac{\tan^2(x)}{\sec^2(x)}\) = ?

- Joined
- Jun 18, 2007

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Read response #2 and #3 and act on itI just went over some notes and realized I missed a section on reduction formulas. That is why none of this is making sense..

So, tan^2 x = (1-cos(2x))/(1+cos(2x)) , I know what the reduction formula is for sin, cos, and tan now, but not sec.