Hint:doubleu said:Hi I'm stuck on the following two problems and would like to ask for help on how to solve them.
Any help will be much appreciated.
I'm confused on the rewrite part how did you get the -5 on the left side?galactus said:For the first one.
Divide through by 2 and get \(\displaystyle \L\\|x-4|<5\)
Rewrite as \(\displaystyle \L\\-5<x-4<5\)
Now, solve for the interval by adding 4.
That's a property of absolute values. \(\displaystyle \L\\|a|<b\) is equivalent to \(\displaystyle \L\\-b<a<b\)I'm confused on the rewrite part how did you get the -5 on the left side?
Just add 4 throughout. \(\displaystyle \L\\-5<x-4<5\)This is what I got from "divide by 2" then "add 4".
You forgot to multiply a by y+1 alsoFor the second one...
I'm not sure how to multiply by (y+1)
I know when I write it, it should be like this...but where do I go from there?
Sorry but I'm even more confused now.galactus said:No.
You cancelled too many y+1.
You should have \(\displaystyle \L\\1+a(y+1)=3\)
Don't cancel the y+1 if there's no division.