How to solve (e) and (f)

The equation of a circle, with center at (1, 0) and radius 1 is (x1)2+y2=1\displaystyle (x- 1)^2+ y^2= 1. The semi-circle above the x-axis is given by y=1(x1)2\displaystyle y= \sqrt{1- (x- 1)^2}. So for (f), [f(x)]2=1(x1)2=2xx2\displaystyle [f(x)]^2= 1- (x-1)^2= 2x- x^2.
 
Top