How to solve (e) and (f)

helpmath00

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helpmath00

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HallsofIvy

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The equation of a circle, with center at (1, 0) and radius 1 is \(\displaystyle (x- 1)^2+ y^2= 1\). The semi-circle above the x-axis is given by \(\displaystyle y= \sqrt{1- (x- 1)^2}\). So for (f), \(\displaystyle [f(x)]^2= 1- (x-1)^2= 2x- x^2\).
 
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