Please show us what you have tried and exactly where you are stuck.
We haven't gotten this far into our lectures, we've just been applying limits.Look at that again. Both the numerator and denominator go to 0 when we take the limit. It may be undefined and it may not be.
Do you know how to use l'Hopital's rule?
This is fine! Remember, lim (a+b) = lim a + lim b, and the same works for products. Cancel out the x, use the e^x limit, and bring it all together in the end.Heres what i've tried, I have a feeling I did something wrong and that it isn't actually undefined.
View attachment 27298
Because once I insert the limit then 3((e^x)-1)/x = 3 because ((e^x)-1)/x=1
However 2x+9x^2 = 2(0)+9(0)^2
So all of it will be (7+3(1))*(1/0) which will give me undefined.