how to solve this ?? n16

First, multiply all the segments by (3 * 2 =) 6 and get rid of the fractional terms.
 
I assume that the question is x3<2x733x+22\displaystyle x-3<\frac{2x-7}{3}\le\frac{3x+2}{2}
If it is then 6x18<4x149x+6\displaystyle 6x-18<4x-14\le 9x+6
Then solve these two and look that the intersection.
6x18<4x14\displaystyle 6x-18<4x-14 and 4x149x+6\displaystyle 4x-14\le 9x+6
 
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I got that
I assume that the question is x3<2x733x+22\displaystyle x-3<\frac{2x-7}{3}\le\frac{3x+2}{2}
If it is then 6x18<4x149x+6\displaystyle 6x-18<4x-14\le 9x+6
Then solve these two and look that the intersection.
6x18<4x14\displaystyle 6x-18<4x-14 and 4x149x+6\displaystyle 4x-14\le 9x+6
I got that but I am unable to solve it
 
I got that I got that but I am unable to solve it
and
\(\displaystyle \begin{align*}6x-18&<4x-14 \\2x&<4\\x&<2 \end{align*}\) and \(\displaystyle \begin{align*}4x-14&\le 9x+6 \\-5x&\le 20\\x&\ge -4 \end{align*}\)

SEE HERE
 
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