Sorry about the poor clarification. I'm not well versed in this subject quite yet. The entire problem is: kids tickets cost $7 and adult tickets cost $10. How many adult and children's tickets are needed to reach $2463 with only 300 total tickets sold. I can find the answer from educated guesses but am not sure how to set up the problem this may have been the reason you did not understand my first question.
So the equation you wrote at first uses variables
K = number of kid tickets
A = number of adult tickets
And you wrote it in a nonstandard way; we usually put the numerical coefficient before the variables. So you meant
7K + 10A = 2463/300
But that's still wrong, because the
total cost is just $2463. There's no division to do.
What you need help with is figuring out where the 300 goes.
Answer: That's the
total number of tickets, which is a separate equation:
K + A = 300
So what you have is a system of two equations in two unknowns. (Don't forget to fix the first one.)
Now the question is, have you learned how to solve such a system? If not, this can be done with only one variable; in effect, you do that by replacing one of the variables in the first equation with the expression you get when you solve for that variable in the second equation.
Now, let's see what more you can do.