I don't know where to start with these problems, Please help

[konniep]

Tx + T + 7x +7
-----------------------
8x +8 i think the answer is t+7
___
8

 

[Denis]

Please have someone who knows how to post properly show you how;
also, read section "Read before posting".

As it is, you post is not understandable.

 

[Loren]

If I am guessing at your post correctly, and you mean
\(\displaystyle \frac{Tx+T+7x+7}{8x+x}=\frac{T+7}{8}\)
you are correct.

 

[masters]

If I am guessing at your post correctly, and you mean
\(\displaystyle \frac{Tx+T+7x+7}{8x+8}=\frac{T+7}{8}\)
you are correct.

Just fixed a little typo in the denominator, Loren.

 

[Denis]

Wonder what the teacher that made that up was trying to teach :shock:

 

[Mrspi]

Wonder what the teacher that made that up was trying to teach :shock:

The benefits of factoring, perhaps??

If you factor the numerator and denominator on the left side, you have this:

[T(x + 1) + 7(x + 1)] / 8(x + 1) = (T + 7) / 8

[ (T + 7)(x + 1)] / 8(x + 1) = (T + 7) / 8

Reduce the fraction on the left side....and you have

(T + 7) / 8 = (T + 7) / 8

NOW...here's the "biggie".....this is true for ALL values of T.

So...I do not think the "solution" is (T + 7) / 8!!

 

[Denis]

Whole thing is completely silly to me; let k = T + 7; then:

(kx + k) / (8x + 8) = k / 8
k(x + 1) / [8(x + 1)] = k / 8
k / 8 = k / 8

Well, good way to mix up an unsuspecting student :shock: