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I don't remember how to find points, given line equation
- Thread starter hape2knit
- Start date
Re: Please help...I don't remember how...
y = (7/8)x - 11
You can find two points on the line this way. Pick a number to use for x (since you are going to be multiplying that value of x by 7/8, it might be a good idea to pick a multiple of 8 to use....and 0 is always a good choice).
Suppose we pick 0 as the value of x. Substitute 0 for x in the equation:
y = (7/8)*0 - 11
y = 0 - 11
y = -11
So, when x = 0, y = -11 and the point (0, -11) is on the line.
Now...pick another value to use for x. Suppose we choose 16 as the value for x. Substitute 16 for x in the equation:
y = (7/8)*16 - 11
You do the arithmetic on the right side to find the value of y...and you'll have the coordinates of another point on the line.
hape2knit said:Please help...find the coordinates of two points on the line with the given equation.
y=7/8x-11
I don't remember how to get rid of the fraction.
Thanks!
y = (7/8)x - 11
You can find two points on the line this way. Pick a number to use for x (since you are going to be multiplying that value of x by 7/8, it might be a good idea to pick a multiple of 8 to use....and 0 is always a good choice).
Suppose we pick 0 as the value of x. Substitute 0 for x in the equation:
y = (7/8)*0 - 11
y = 0 - 11
y = -11
So, when x = 0, y = -11 and the point (0, -11) is on the line.
Now...pick another value to use for x. Suppose we choose 16 as the value for x. Substitute 16 for x in the equation:
y = (7/8)*16 - 11
You do the arithmetic on the right side to find the value of y...and you'll have the coordinates of another point on the line.
Re: Please help...I don't remember how...
Do you remember that by multiplying both sides of an equation by a non-zero number you change the looks of the equation? Both equations have same characteristics. The graphs of the two equations will be the same. Therefore you can do the "choose a number" thing for either equation and you will get the same result.
y=(7/8)x-11........If x=8 then y=-4. The point (8,-4) satisfies the equation.
8y=7x-88...........If x=8 then 8y=56-88, 8y=-32, y=-4. Same result as above.
Do you remember that by multiplying both sides of an equation by a non-zero number you change the looks of the equation? Both equations have same characteristics. The graphs of the two equations will be the same. Therefore you can do the "choose a number" thing for either equation and you will get the same result.
y=(7/8)x-11........If x=8 then y=-4. The point (8,-4) satisfies the equation.
8y=7x-88...........If x=8 then 8y=56-88, 8y=-32, y=-4. Same result as above.