I got no clue

dollyayesha2345

Junior Member
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Oct 28, 2021
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57
Question: Find a real number between 1 and[imath]\sqrt3[/imath]

My approach(which is wrong): [imath]\frac{a+b}{2}[/imath]
[math]\frac{1+1.732}{2}[/math][math]=\frac{2.732}{2}[/math][math]=1.366[/math]So a real number between 1 and[imath]\sqrt3[/imath] is 1.3.

Please tell me whether my approach and answer is correct or not. If not then do guide me on how to solve this.
 
Question: Find a real number between 1 and[imath]\sqrt3[/imath]

My approach(which is wrong): [imath]\frac{a+b}{2}[/imath]
[math]\frac{1+1.732}{2}[/math][math]=\frac{2.732}{2}[/math][math]=1.366[/math]So a real number between 1 and[imath]\sqrt3[/imath] is 1.3.

Please tell me whether my approach and answer is correct or not. If not then do guide me on how to solve this.
I agree that your answer is correct, and the method is good; it's probably good to add that there are very many (infinitely many!) other correct answers, such as (picking two randomly) 1.71629, and 5/3 = 1.666... .

What's good about your method is that it is guaranteed to produce a number between the two given numbers, whatever they were. So your answer is better in some sense than mine!
 
I just noticed one more thing I should have said.

The method I said could be considered "better" than mine in a sense would stop at [imath]\frac{1+\sqrt{3}}{2}\approx 1.366[/imath]. When you rounded that down to 1.3, you were actually doing the same thing I did, looking at the digits of a value and choosing a number between 1 and that number! Your final answer is a rational number in the interval; your method found an irrational number, which is a very nice answer to the question.
 
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