#### Jomo

##### Elite Member

- Joined
- Dec 30, 2014

- Messages
- 3,658

Here is what I have done so far.

The 1st scenario. The family has two children and at least one is a girl. So the family has either gb, bg or gg. In one of the three cases there is a 2nd girl. So p=1/3. I am certain that this is correct.

2nd case. The family has two children and at least one is a girl born in April.

The family can have either bg(girl in April), gb(girl in April), gg (1st girl in April) or gg (2nd girl in April). Note that the 'other girl' (if there is one) could have been born in April as well.

Now in the 1st case the given girl could have been born in any of the 12 month and in this case we are told April.

So is the answer for q, q= 2/4 = 1/2 because we have 4 cases in the 2nd scenario? Well that is only true if the four possibilities are all equally likely. I am not totally convinced that that is true.

Any takers on how to explain this? Thanks