keboehringer
New member
- Joined
- Aug 28, 2020
- Messages
- 2
If a ball is thrown straight up into the air with an initial velocity of 40 ft/s, its height in feet after t second is given by y=40t−16t^2. Find the average velocity for the time period beginning when t=1 and lasting
- 0.1 seconds
- 0.01 seconds
- 0.001 seconds
- Finally based on the above results, guess what the instantaneous velocity of the ball is when t=1?