I need help with Find the derivative. Assume that I and R are functions of t.

Dr_fox

New member
d/dt(IR^2) first i use the chain rule and got 2R(I,t)d/dt(R(I,t) then took the derivative of R(I,t) wich is I2R(I,t)d/dt(R

Subhotosh Khan

Super Moderator
Staff member
d/dt(IR^2) first i use the chain rule and got 2R(I,t)d/dt(R(I,t) then took the derivative of R(I,t) wich is I2R(I,t)d/dt(R
Did you have a question?

$$\displaystyle \frac{dIR^2}{dt}=\frac{dI}{dt}R^2+ I\frac{dR^2}{dt}$$
$$\displaystyle = \frac{dI}{dt}R^2+2IR\frac{dR}{dt}$$.