Here is the two algebraic equations I have here I am stumped on.

1. 4y(y+y/2+8)=120

4y(y+y/2+8)=120

4y(3y/2+8)-120=0

distribute the 4y ...

6y[sup:3qjch0ma]2[/sup:3qjch0ma] + 32y - 120 = 0

2(3y[sup:3qjch0ma]2[/sup:3qjch0ma] + 16y - 60) = 0

3y[sup:3qjch0ma]2[/sup:3qjch0ma] + 16y - 60 = 0

now use the quadratic formula to solve for y

2. The sum of three consecutive even numbers is 150. Find the numbers.

How would you convert this into an algebraic equation?

This is what I put down.

50,100,150 would be three consecutive numbers is 150. You see that is why I need help for these problems right here.

50, 100, and 150 are not consecutive even integers.

an example ... 8, 10, and 12 are **three consecutive even** integers.

you are to find three consecutive even integers whose sum is 150.

let x = the first even integer

x+2 = the next even integer

x + 4 = the third consecutive even integer. set the sum these consecutive even integers equal to 150 and solve for x.