Video343(as on IGN) said:

I;m seriously sorry I know I'm not supposed to ask this way but I need some help.

"A ball is tossed upward with an initial velocity of 42.5 feet per second. The equation below shows the velocity (v) of the ball after "t" secconds."

v=-32t+42.5

"After how/now many secconds is the velocity 0 feet per seccond? Round the answer to the nearest tenth of a seccod?"

Try to notice relationships between the given information and the problem statement.

Given: The equation below shows the velocity (v) of the ball after "t" secconds.

Problem: After how many seconds is the velocity 0 feet per seccond?

'v' changes with 't'

v(t) = -32t+42.5

v(0) = -32(0) + 42.5 = 0+42.5 = 42.5

v(1) = -32(1) + 42.5 = -32+42.5 = 10.5

v(2) = -32(2) + 42.5 = -64+42.5 = -21.5

It looks to me like the anwser is somewhere between t = 1 and t = 2. Can you solve it directly?