this is the question

Suppose that a car can accelerate from 30 mph to 50 mph in 4 seconds. Assuming a constant acceleration,

find the acceleration (in miles per second squared) of the car and find the distance traveled by the car during the 4 seconds.

logistic_guy,

for this first question (before converting it to the required units), the acceleration =

\(\displaystyle \ \dfrac{(final \ velocity \ in \ mph) \ minus \ (initial \ velocity \ in \ mph)}{travel \ time \ in \ sec} \)

The final velocity is 50 mph.

The initial velocity is 30 mph.

The travel time is 4 sec.

However, the units for acceleration required for the answer is miles per sec per sec.

Already discussed above in at least one other post is a conversion for

miles per sec per sec.

I don't know if that discussion is finished.

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For the second question, do any of the formulas posted in post # 13 work?

Suppose this is not the case.

Since the problem is dealing with miles per hour, it would make sense to me

to find the number of

**feet ** that the car has traveled during the four seconds.

To do that, we should convert 30 mph and 50 mph to the appropriate numbers

of feet per sec each.

We could estimate the distance using rate*time by using 10 intervals, for instance:

Midpoints second marks 3.1, 3.3, 3.5, 3.7, 3.9, 4.1, 4.3, 4.5, 4.7, 4.9

Multiply these by their respective velocities and add them up.