identities: 1/tanx = cotx/ sin^2x + cos^2x

[ca.chick]

i am not sure how to figure this out:

it has to be equal to each other and i got stuck:

1/tanx = cotx/ sin^2x + cos^2x

i know that I should reduce the harder side, but i dont know how it would end up to be 1/tanx

 

[morson]

I assume you meant:

\(\displaystyle \frac{1}{tanx}\ = \frac{cotx}{sin^2x + cos^2x}\ , tanx \not=\ 0\)

This really is very easy if you know what \(\displaystyle sin^2x + cos^2x\) is. If you don't, learn it before you attack any of these problems as it's essential. Also, you'll need to know what \(\displaystyle cotx\) is equal to.