- Thread starter KebabYa
- Start date

- Joined
- Jun 16, 2019

- Messages
- 5

74x = 214 * 10Hi there,

I’m terrible at maths but always come across problems like this, so its probably really simple.

how would i go about working this out on a calculator?

If 74 grams = 214 kcal

What would 10 grams be

,thanks

Now x = 2140÷ 74

=28.92

This is direct proportion so u need to cross mutiply

I wouldnt know how to get to 1 gram.

i would of never of worked that out, That makes total sense,74x = 214 * 10

Now x = 2140÷ 74

=28.92

This is direct proportion so u need to cross mutiply

Thank you,

Well, provided the fully worked answer truly helped you understand the concepts at play rather than just learn how to solve this one problem, you now know that the intended operation to figure out how many kilocalories in 1 gram was division. But given your apprehension and self-deprecating attitude (re: being "terrible at maths"), it will likely be helpful to play around with it some and seeHi ksdhart, thanks for the reply.

I wouldnt know how to get to 1 gram.

Let's consider some other, simpler examples. Suppose you had two apples and you wanted to equally distribute them into two buckets. How many apples would you put in each bucket? Likewise, what if you had three apples and three buckets? Okay, so, obviously the answer in both cases is 1 apple per bucket, but how did you figure that out? You used

In the actual problem at hand, you have 214 "apples" and 74 "buckets," so the answer won't be a nice whole number. However, the

that’s fantasticWell, provided the fully worked answer truly helped you understand the concepts at play rather than just learn how to solve this one problem, you now know that the intended operation to figure out how many kilocalories in 1 gram was division. But given your apprehension and self-deprecating attitude (re: being "terrible at maths"), it will likely be helpful to play around with it some and seewhydivision is appropriate to use here.

Let's consider some other, simpler examples. Suppose you had two apples and you wanted to equally distribute them into two buckets. How many apples would you put in each bucket? Likewise, what if you had three apples and three buckets? Okay, so, obviously the answer in both cases is 1 apple per bucket, but how did you figure that out? You useddivision\(\displaystyle \left( \frac{2 \: apples}{2 \: buckets} = \frac{3 \: apples}{3 \: buckets} = \frac{1 \: apple}{1 \: bucket} \right)\). Now, what would happen if you had six apples and two buckets? Or what if you had twelve apples and three buckets? As before, the answers should be very easy to work out, but the point here is to take a step back and consider how you got those answers, and why you used the operations you did.

In the actual problem at hand, you have 214 "apples" and 74 "buckets," so the answer won't be a nice whole number. However, theprocessis what's important here, and the process remains the exact same, even when the numbers cause you grief by not playing nicely.

It makes total sense now

Thank you

- Joined
- Mar 21, 2016

- Messages
- 11