If (a-b)^-2/5 = (a+b)^2/5 , what is the value of (a^2-b^2)?

[swagmoney]

Hi,

I need help solving the below question.

If (a-b)^-2/5 = (a+b)^2/5 , what is the value of (a^2-b^2)?

Thanks!

 

[Deleted member 4993]

Hi,

I need help solving the below question.

If (a-b)^-2/5 = (a+b)^2/5 , what is the value of (a^2-b^2)?

Thanks!

Use:

(a-b)^-2/5 = 1/[(a-b)^2/5] and

(a^2 - b^2) = (a+b) * (a-b)

 

[lookagain]

Hi,

I need help solving the below question.

If (a-b)^-2/5 = (a+b)^2/5 , what is the value of (a^2-b^2)?

Thanks!

swagmoney, you need grouping symbols around the exponents because of the Order of Operations. **


(a - b)^(-2/5) = (a+b)^(2/5)


- - - - - - - - - - - - ---- - - - - - - -- - - - - - -- -- - - -

Use:

(a-b)^-2/5 = 1/[(a-b)^2/5]

(a - b)^(-2/5) = 1/[(a - b)^(2/5)] \(\displaystyle \ \ \ \ \ \ \ \) See ** above.

 

[Deleted member 4993]

(a - b)^(-2/5) = 1/[(a - b)^(2/5)] \(\displaystyle \ \ \ \ \ \ \ \) See ** above.

Thank you ... Lookagain