I think that's very clever-way to decipher that problem.I get a headache thinking about it; but:
2 different diagonals possible on each of the 6 faces;
let 1 and 2 represent them; then:
01 : 111111
02 : 111112
03 : 111121
62 : 222212
63 : 222221
64 : 222222
2^6 = 64
That's how I "see" this...
Subhotosh will probably send me to the corner...
Hi bennyJ,Perhaps this is a more precise way to ask the same question:
How many distinct patterns are possible if each side of a cube has a diagonal drawn across it and if one counts as one pattern any patterns that can be made to coincide by various rotations of the cube as one rigid object?