ok, then we get X² + 1/X² = 46
hi, ok I did, but it equals 322, right?
\(\displaystyle \begin{align*}{x^3} + \frac{1}{{{x^3}}} &= \left( {x + \frac{1}{x}} \right)\left( {{x^2} - x\left( {\frac{1}{x}} \right) + \frac{1}{{{x^2}}}} \right)\\& = 7\left( {{x^2} + \frac{1}{{{x^2}}} - 1} \right)\\& = 7\left( {48 - 1} \right)\\& = ~? \end{align*}\)IF: X² + 1/X² = 48
and X + 1/X = 7
then prove that X³ + 1/X³ = 329