This is what I did

1/5 + 1/5 + 1/5 + 1/5 + 1/5 (because I know that I would need 5 to make a whole second) = 20 x 5 = 100

I actually did the above two more times and reached my answer of 300.

Help, I am sure that there was an easier way to do this.

- Thread starter atwana_b
- Start date

This is what I did

1/5 + 1/5 + 1/5 + 1/5 + 1/5 (because I know that I would need 5 to make a whole second) = 20 x 5 = 100

I actually did the above two more times and reached my answer of 300.

Help, I am sure that there was an easier way to do this.

(distance = rate * time)

d = 20 feet

r = ?

t = (1/5) second

manipulate d=rt so that you get an equation for R: r = d/t

r = 20/(1/5)

r = 100 feet/second

now, use D(t)=RT

D(3) = 100(3)

D(3) = 300

There is your answer

D(3) means "the value of D when T=3"

1/5 sec = 20atwana_b said:A train travels 20 feet in 1/5 second. At this same speed, how many feet will it travel in three seconds.

1 sec = 20 * 5 = 100

3 sec = 300

Your reasoning is correct.

That kind of logic is a

Here's another intuitive approach: . . . . . \(\displaystyle \frac{1}{5}\text{ second}\:\rightarrow\: 20\text{ feet}\)

. . . . . . Multiply both sides by 15: \(\displaystyle \;15\,\times\,\left(\frac{1}{5}\text{ second}\right) \;\rightarrow\;15\,\times\,(20\text{ feet})\)

. . . . . . . . . . . . . . . . and we get: . . . . \(\displaystyle 3\text{ seconds}\;\rightarrow\;300\text{ feet}\)