#### Harry_the_cat

##### Full Member

- Joined
- Mar 16, 2016

- Messages
- 943

I just saw on Facebook a post asking to solve \(\displaystyle 6 \div2(1+2)\) with many different answers proffered (many obviously incorrect).

I usually do not respond to these posts but enjoy seeing incorrect answers being vigorously defended by some people.

This was my response this time:

The issue with this question is your interpretation of the "missing" multiplication sign. Does it mean: \(\displaystyle 6\div 2(1+2)=3*3=9\) or does it mean \(\displaystyle 6\div(2(1+2))=6\div6=1\) ? A "missing" or implicit multiplication sign implies a second set of brackets, so the correct answer is 1. If the multiplication sign was explicit, then the correct answer would be 9. So in this case, 1 is the correct answer.

Am I correct?

I usually do not respond to these posts but enjoy seeing incorrect answers being vigorously defended by some people.

This was my response this time:

The issue with this question is your interpretation of the "missing" multiplication sign. Does it mean: \(\displaystyle 6\div 2(1+2)=3*3=9\) or does it mean \(\displaystyle 6\div(2(1+2))=6\div6=1\) ? A "missing" or implicit multiplication sign implies a second set of brackets, so the correct answer is 1. If the multiplication sign was explicit, then the correct answer would be 9. So in this case, 1 is the correct answer.

Am I correct?

Last edited: