WAIT SORRY I misread thatWhat is the limit as \(b\to\infty~?\)
\(\displaystyle\left. { - {e^{ - x}}(x + 1)} \right|_0^b = \left[ { - {e^{ - b}}(b + 1)} \right] - \left[ { - 1(1)} \right]\)WAIT SORRY I misread that What I meant to say was, I do not know how to compute that.
Please write down the limit you are having trouble with, so everyone is on the same page, state why you are having trouble and you will be expertly helped. Fair enough?
\(\displaystyle\left. { - {e^{ - x}}(x + 1)} \right|_0^b = \left[ { - {e^{ - b}}(b + 1)} \right] - \left[ { - 1(1)} \right]\)
Now what is the limit as \(b\to\infty \)
CORRECTI believe that the limit would be 1, considering that E is raised to the power of negative infinity