#### jedediahjamez

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How do I go about solving 3[SUP]x^2+x[/SUP]=9. Thanks in advance

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How do I go about solving 3[SUP]x^2+x[/SUP]=9. Thanks in advance

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Hint: Write 9 as 3^2

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Thank you, but I’m still confused as to what to do with having 2 x variables. I’m sorry if I sound stupid but I’m a new student and I have a terrible teacher. Thanks againHint: Write 9 as 3^2

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3^(x^2 + x) = 3^2

This equation shows two powers of 3 set equal to one another. Can you use a basic property of exponents, to write another equation where x does not appear in any exponents?

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So the answer would be x=1 right? My school uses an online system to do homework and it’s telling me x=1 is wrong?

3^(x^2 + x) = 3^2

This equation shows two powers of 3 set equal to one another. Can you use a basic property of exponents, to write another equation where x does not appear in any exponents?

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That's part of the answer.So the answer would be x=1 right?

Did you write (and maybe solve) a new equation, as I suggested? If so, may I see the equation and your work?

If you did not solve an equation, how did you get x = 1?

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Given

In other words, if two powers of the

(

If you apply this property to the given equation in your exercise (after substituting 3^2 for 9), you'll get a basic quadratic equation to solve for x. (There are two solutions.)

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Please reply showing how you followed through on the steps and hints you were provided. You created the equation they'd almost given you, you solved this using the Quadratic Formula, you got the two values, and... how did you get that "x=1" is the only answer?So the answer would be x=1 right? My school uses an online system to do homework and it’s telling me x=1 is wrong?

Please be complete. Thank you!

Well clearly x = 1 isSo the answer would be x=1 right? My school uses an online system to do homework and it’s telling me x=1 is wrong?

\(\displaystyle x = 1 \implies x = 1 \implies x^2 = 1 \implies x^2 + x = 1 + 1 = 2 \implies 3^{(x^2 +x)} = 3^2.\)

But x = 1 is not the