- Thread starter ns.19
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I've tried, but, I couldn't solve this problemWho says you are wrong? Have you yet used the fact that Triangle BDA is isosceles? That may lead somewhere.

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For the record I too get an infinite solution. I of course looked at BDA being isosceles but that did not help.

I recall a similar problem like this where Dr Peterson showed that there is a unique solution. If there is one I am sure that someone will point this out and state why. Meanwhile keep trying.

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Yes, that is just what I got, just with different lettering. I agree that the system you came up with does not have a solution. However what you have is more than just a system of equations, you have a geometric figure that can influence things. For example, d, z and y can't be negative. Possibly there is something else which we are missing that can make this problem uniquely solvable.

I think there is a unique solution (by construction?): ABC has angles 50, 50, 80. Point D is uniquely defined by the 10 degree angles. Therefore angle x is uniquely defined.Yes, that is just what I got, just with different lettering. I agree that the system you came up with does not have a solution. However what you have is more than just a system of equations, you have a geometric figure that can influence things. For example, d, z and y can't be negative. Possibly there is something else which we are missing that can make this problem uniquely solvable.

If you drop heights from D to AC and AB and make |AB| = 1 you can calculate everything using sin and cos of known angles. There is probably an easier way to do it.

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I am not saying that you did not supply all the information. I am saying that possibly we are missing something that is a result of what you gave us.I understand, but, this question was passed on to me only in this way. Without any more information.

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Nicely done! I am embarrassed at how poorly I do with geometry. I really have no talent in this subject. Your method was so obvious. Thanks for pointing it out to me and the OP and increasing my geometry maturity!I think there is a unique solution (by construction?): ABC has angles 50, 50, 80. Point D is uniquely defined by the 10 degree angles. Therefore angle x is uniquely defined.

If you drop heights from D to AC and AB and make |AB| = 1 you can calculate everything using sin and cos of known angles. There is probably an easier way to do it.