inequalitie problem

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hello, i'm trying to solve:

6x-(2x+3) =>4x-5

i keep getting -3=>5, this can't be right.

can someone tell me what i'm doing wrong? first thing i do is distribute the negative.


( => is greator than/equal to )

 

[pka]

\(\displaystyle \L
6x - (2x + 3) \ge 4x - 5\quad \Rightarrow \quad - 3 \ge - 5\)

Is that always true?

 

[mmm4444bot]

If you end up with a false statement, then there are no solutions.

~ Mark

 

[pka]

But in this case it is true!
So it is true for every x.
The solution set is the set of real numbers.

 

[mmm4444bot]

Whoopsie Daisy!

But in this case it is true!
So it is true for every x.

I should have checked relapse's work before posting so quickly. Serves me right.

~ Mark

 

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so i have the correct answer?

 

[Gene]

After you correct the sign on the 5
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Gene