Inequalities problem

[Shmuco]

I worked this out to be -1 x by converting them to the same base. I put it into a desmos to graph but it says thats no correct. Any help would be appreciated.

 

[Deleted member 4993]

I worked this out to be -1 View attachment 20348 x by converting them to the same base. I put it into a desmos to graph but it says thats no correct. Any help would be appreciated.

Please follow the rules of posting in this forum, as enunciated at:

https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520

Please share your work/thoughts about this assignment.

 

[Shmuco]

Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:

https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520

Please share your work/thoughts about this assignment.
View attachment 20350

 

[Dr.Peterson]

You are assuming that if [MATH]a^{-1} \le a^x[/MATH], then [MATH]-1\le x[/MATH]. There is no such rule!

Have you considered what happens if the base is negative, or if it is zero? I would probably try splitting the problem into three cases based on that. (You will find that two cases are, in some sense, "simple".)