Inequalities with fractions: 8/x+1 + 6/x-1 = 5

[lroux]

I need to solve for x: 8/x+1 + 6/x-1 = 5

I know I need to divide first but after that I can't figure it out...

Help!

LEE

 

[Deleted member 4993]

No.... you need to multiply both sides by [(x+1)*(x-1)] - the LCD of the left-hand-side.

 

[lroux]

yes, multipy, then I am left with 8/x+1+6(x-1) = x-1(x-1) thats when I get stuck, multipying the left side.

LEE

 

[Denis]

yes, multipy, then I am left with 8/x+1+6(x-1) = x-1(x-1) thats when I get stuck, multipying the left side.
LEE

Sorry Lee, but that makes no sense whatsoever.
Also, you need brackets: 8 / (x+1).
You need your math teacher's help.

 

[stapel]

I need to solve for x: 8/x+1 + 6/x-1 = 5

Your subject line refers to "inequalities". If this is indeed an inequality, then the solution technique is different from that for an equation. :shock:

Please reply with clarification, including parentheses. Thank you!

Eliz.

 

[lroux]

O.K. I will try again...

I need to solve for x

8/(x+1) + 6/(x-1) = 5

I need to multipy by the LCD which is (x + 1)(x - 1), then I am left with
(8x-8) + (6x+6) = 5(x+1)(x-1), at this point I know I am doing something wrong because it does not calculate correctly.

LEE

 

[pka]

(8x-8) + (6x+6) = 5(x+1)(x-1), at this point I know I am doing something wrong because it does not calculate correctly.

You are correct to that point.
14x-2=5(x<SUP>2</SUP>-1)
Now finish.