inequality

kanali

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Jun 12, 2010
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Prove the following inequality:

xyzx+y+z2\displaystyle xyz\geq x+y+z-2 for x1,y1,z1\displaystyle x\geq 1,y\geq 1,z\geq 1.


i can only think of squaring the equation but would that help??
 
kanali said:
Prove the following inequality:

xyzx+y+z2\displaystyle xyz\geq x+y+z-2 for x1,y1,z1\displaystyle x\geq 1,y\geq 1,z\geq 1.


i can only think of squaring the equation but would that help??

I have not totally thought it through - but I think following identity might help:

a3  +  b3  +  c3    3abc  =  (a  +  b  +  c)(a2  +  b2  +  c2    ab    bc    ca)\displaystyle a^3 \ \ + \ \ b^3 \ \ + \ \ c^3 \ \ - \ \ 3abc \ \ = \ \ (a \ \ + \ \ b \ \ + \ \ c)\cdot (a^2 \ \ + \ \ b^2 \ \ + \ \ c^2 \ \ - \ \ ab \ \ - \ \ bc \ \ - \ \ ca)
 
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