J jenna89 New member Joined Nov 3, 2008 Messages 11 Dec 1, 2008 #1 Could you help me with the problem below: ?(x^2+3)(3x^2-4x+6)dx ?x^2+1/2+1 dx+3?x dx + 3?x^2+1/2+1 dx-4?1x+6?x ?x^3/3 + 3x dx +3?x^3/3 dx-4?1x+6?x thanks
Could you help me with the problem below: ?(x^2+3)(3x^2-4x+6)dx ?x^2+1/2+1 dx+3?x dx + 3?x^2+1/2+1 dx-4?1x+6?x ?x^3/3 + 3x dx +3?x^3/3 dx-4?1x+6?x thanks
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Dec 1, 2008 #2 Re: integrals Are you trying partial fractions?. \(\displaystyle \int\frac{x^{2}+3}{3x^{2}-4x+6}dx=\frac{4}{3}\int\frac{x}{3x^{2}-4x+6}dx+\int\frac{1}{3x^{2}-4x+6}dx+\frac{1}{3}\int dx\) Can you think of a u-sub to try?. \(\displaystyle x=\frac{u+2}{3}\) may be helpful.
Re: integrals Are you trying partial fractions?. \(\displaystyle \int\frac{x^{2}+3}{3x^{2}-4x+6}dx=\frac{4}{3}\int\frac{x}{3x^{2}-4x+6}dx+\int\frac{1}{3x^{2}-4x+6}dx+\frac{1}{3}\int dx\) Can you think of a u-sub to try?. \(\displaystyle x=\frac{u+2}{3}\) may be helpful.
