Integrals

[Ian McPherson]

I don't know how to do all the symbols so forgive me

its The integral sign of 3x^4 dx
(2x^5 - 5)^4

So don't i rearrange it to Integral (2x^5 - 5)^4 * (3x^4)

then (2x^5 - 5)^4 * 3/10 * (3x^4) Multiply by 3/10 because the second parentheses starts with three and the needed matched derivative would be 10 (from derivative of 2x^5)

then isn't it 3/10 Integral (2x^5-5)^4
then use the power rule to get 3/10 Integral (2x^5-5)^5
5

then i thought you'd multiply the 3/10 into that. But that isn't the correct answer and I don't know exactly why. I missed lecture today due to a migraine, so I'm going off of the examples in the book so forgive me for any dumb errors.

 

[pka]

I don't know how to do all the symbols so forgive me its The integral sign of
3x^4 dx
(2x^5 - 5)^4

Let \(\displaystyle u=2x^5-5\) then the integral becomes \(\displaystyle \frac{3}{{10}}\int {u^{ - 4} du} .\)

 

[Ian McPherson]

Oh because U i on the bottom of the fraction, so when it's brought up the exponent has to be negative....thanks!