R refid New member Joined Dec 29, 2005 Messages 23 May 21, 2006 #1 I have no clue how to intergrate this one can sume help. . . . . . Integrate: \(\displaystyle \large{\int{\,|x|dx}\) b =1 a=-1 i have tried . . . . .Integrate: \(\displaystyle \large{\int{\,|x|dx} ={\,|x^2/2|}\) does not work out
I have no clue how to intergrate this one can sume help. . . . . . Integrate: \(\displaystyle \large{\int{\,|x|dx}\) b =1 a=-1 i have tried . . . . .Integrate: \(\displaystyle \large{\int{\,|x|dx} ={\,|x^2/2|}\) does not work out
pka Elite Member Joined Jan 29, 2005 Messages 11,978 May 21, 2006 #2 Use the definition of absolute value: \(\displaystyle \L \int\limits_{ - 1}^1 {|x|dx} = \int\limits_{ - 1}^0 {-xdx + } \int\limits_0^1 {xdx}\)
Use the definition of absolute value: \(\displaystyle \L \int\limits_{ - 1}^1 {|x|dx} = \int\limits_{ - 1}^0 {-xdx + } \int\limits_0^1 {xdx}\)
R refid New member Joined Dec 29, 2005 Messages 23 May 21, 2006 #3 \(\displaystyle \L \int\limits_{ - 1}^1 {e^{|x|}dx} = \int\limits_{ - 1}^0 {e^-^x dx + } \int\limits_0^1 {e^xdx}\) would this be correct as well?
\(\displaystyle \L \int\limits_{ - 1}^1 {e^{|x|}dx} = \int\limits_{ - 1}^0 {e^-^x dx + } \int\limits_0^1 {e^xdx}\) would this be correct as well?
