S Sonal7 Full Member Joined Oct 4, 2019 Messages 318 Nov 24, 2019 #1 I cant see the error. The option 2 is wrong when I click on it. Please see my working, I thought it would be the right answer Attachments 20191124_190839.jpg 1.2 MB Views: 7 Screenshot 2019-11-24 at 19.08.07.png 39.8 KB Views: 6
I cant see the error. The option 2 is wrong when I click on it. Please see my working, I thought it would be the right answer
S Subhotosh Khan Super Moderator Staff member Joined Jun 18, 2007 Messages 21,224 Nov 24, 2019 #3 Sonal7 said: I got it how c isnt 0!!! Click to expand... Your integration was incorrect. It should have been: y * e2x = (1/2)*x * e2x - (1/4) * e2x + C Now apply at x=0, we have y = 0 \(\displaystyle \to\) C = 1/4
Sonal7 said: I got it how c isnt 0!!! Click to expand... Your integration was incorrect. It should have been: y * e2x = (1/2)*x * e2x - (1/4) * e2x + C Now apply at x=0, we have y = 0 \(\displaystyle \to\) C = 1/4
S Sonal7 Full Member Joined Oct 4, 2019 Messages 318 Nov 25, 2019 #4 Ah stupid mistake. I got it now. thanks a lot
