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1+ tan²x =sec²x.
∫sec³ x dx using integration by parts
The formula for integration by parts Is1+ tan²x =sec²x.
∫sec³ x dx using integration by parts ........U= sec x du=secx tanx dv=sec²x v=tanx .......So here is what I did,
∫sec³x = ∫sec²x X sec x...........= secx tanx x ∫secx tan²x dx ...........incorrect ...........And I'm stuck here
The formula for integration by parts Is
\(\displaystyle \int u(x) \ d[v(x)] = u(x) * v(x) - \int v(x) \ d[u(x)]\)
What did you assign as u(x) and v(x)?
The formula for integration by parts Is
\(\displaystyle \int u(x) \ d[v(x)] = u(x) * v(x) - \int v(x) \ d[u(x)]\)
First you really need to separate your equals possible by using commas!!
u= sec x, du=secx tanxdx, dv=sec²x, v=tanx
Do NOT use x as a variable and X for the multiplication symbol. Use * for multiplication.
You made a little mistake with the formula. Replace X with -
After you fix the little mistake you made in that last integral you should substitute tan^2(x) with sec^2(x) - 1
Post back with your work.
What did you assign as u(x) and v(x)?
1+ tan²x =sec²x.First you really need to separate your equals possible by using commas!!
u= sec x, du=secx tanxdx, dv=sec²x, v=tanx
Do NOT use x as a variable and X for the multiplication symbol. Use * for multiplication.
You made a little mistake with the formula. Replace X with -
After you fix the little mistake you made in that last integral you should substitute tan^2(x) with sec^2(x) - 1
Post back with your work.
U(
1+ tan²x =sec²x.
∫sec³ x dx using integration by parts
U= sec x, du=secxtanx dx, dv=sec²x , v=tanx
So here is what I did,
∫sec³x dx = ∫sec²x * sec x
= secx tanx -∫secx tan²x dx
=secx tanx-∫secx*(sec²x-1) dx (?)