integration: integrate y/(1 + y^2) dy

[markosheehan]

find ∫ y/(1+y²) dy the answer is 1/2 ln(1+y²) how does it work out this way? what rule is being used

 

[Deleted member 4993]

find ∫ y/(1+y²) dy the answer is 1/2 ln(1+y²) how does it work out this way? what rule is being used

substitute

u = 1 + y²

du = 2y dy

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