anupjsebastian
New member
- Joined
- Feb 20, 2018
- Messages
- 3
Both these integrals should yield the same result as -x+1 = -(x-1)
so 1/(-x+1) = 1/-(x-1)= -1/(x-1)
however one integrates to -ln(1-x) and the other to -ln(x-1)
x-1 is not equal to 1-x for all values except x = 1
so is the integral only defined for x = 1?
but it is possible to plot the integral over multiple values...
could someone please explain what is actually happening here..
thanks
so 1/(-x+1) = 1/-(x-1)= -1/(x-1)
however one integrates to -ln(1-x) and the other to -ln(x-1)
x-1 is not equal to 1-x for all values except x = 1
so is the integral only defined for x = 1?
but it is possible to plot the integral over multiple values...
could someone please explain what is actually happening here..
thanks