log(u) - 1/2 log(1-u^2)=t ?
You write:Not entirely sure if I'm on the right path, so my working so far:
ln(u)-ln(1-u^2)/2 + c = t + c
ln(u)-ln(1-u^2)/2 = t
2ln(u) - ln(1-u^2) = 2t
ln(u^2/(1-u^2) = 2t
u^2/(1-u^2) = e^2t
Any feedback on that working would be really helpful, thanks
can you not cancel out the c's as they're on both sides?You write:
ln(u)-ln(1-u^2)/2 + c = t + c
ln(u)-ln(1-u^2)/2 = t...........................where did 'c' go?
2ln(u) - ln(1-u^2) = 2t
No - those need not be equal.can
you not cancel out the c's on both side?
you ok to explain what you mean by this, because how do I look to carry on the proof if I'm trying to get terms on one side so I have u=No - those need not be equal.
ln(u)-ln(1-u^2)/2 + c1 = t + c2You write:
ln(u)-ln(1-u^2)/2 + c = t + c
ln(u)-ln(1-u^2)/2 = t...........................where did 'c' go?
2ln(u) - ln(1-u^2) = 2t