cheetahday
New member
- Joined
- Jan 14, 2015
- Messages
- 1
∫x(xp+a)dx, where a,p=0. Use the substitution u=1+ax−p.
So far I've only gotten
x^p=(u-1)/a
x=((u-1)/a)^(1/p)
I'm stuck everything I plug in just becomes really messy
So far I've only gotten
x^p=(u-1)/a
x=((u-1)/a)^(1/p)
I'm stuck everything I plug in just becomes really messy
Last edited by a moderator: